Levi Randolph joins Zenit!

Zenit Basketball Club and American guard Levi Randolph have agreed to terms. The 32-year-old has signed a two-year deal that will keep him in Saint Petersburg through the end of the 2026/27 season.

Levi Randolph was born on October 3, 1992, in Madison, Alabama, USA. Early in his career, the guard played four years for the University of Alabama Crimson Tide in the NCAA and took part in the 2015 NBA Draft.

Randolph’s first professional team was the Maine Red Claws — the G League affiliate of the Boston Celtics. In the 2015/16 season, he played 52 games, averaging 14.7 points, 4.8 rebounds, 2.8 assists and 1.0 steals per game.

The following season marked his first move to Europe, and from then on, he mostly played overseas. Between 2016-2018 and 2021-2024, Levi played for Italian teams  Sidigas Avellino and Dinamo Sassari, French club SIG Strasbourg, the New Zealand Breakers, Belgian side Oostende, and Israeli team Hapoel Jerusalem. During this time, the guard won the French Cup, became both Belgian League Champion and Supercup winner, claimed the Israeli Cup three times, and was named the MVP of the Belgian League.

An exception in his international career came during a three-year stint with the Cleveland Cavaliers’ G League affiliate, the Canton Charge, where he played from 2018 to 2021.

In the 2024/25 season, Randolph played for Maccabi Tel Aviv. Making his EuroLeague debut, he appeared in 33 games, averaging 12.0 points, 3.8 rebounds, and 1.8 assists. In the Israeli League, he averaged 13.2 points, 3.7 rebounds, and 1.7 assists per game.

 

The Blue-White-Sky Blues are excited to welcome Levi to the squad and wish him continued success in Saint Petersburg!